The length of the second’s pendulum on the surface of the earth is 1m. The length of the same pendulum on the surface of the moon, where the acceleration due to gravity is (⅙)th of the g on the surface of the earth is
1.36 m
2.1m
3.1/36 m
4.⅙ m
Answer:4
Posted Date:-2021-12-08 03:14:20