What will be the output of the following Python code snippet? numbers = {} letters = {} comb = {} numbers[1] = 56 numbers[3] = 7 letters[4] = 'B' comb['Numbers'] = numbers comb['Letters'] = letters print(comb)
1.Error, dictionary in a dictionary can’t exist
2. ‘Numbers’: {1: 56, 3: 7}
3.{‘Numbers’: {1: 56}, ‘Letters’: {4: ‘B’}}
4.{‘Numbers’: {1: 56, 3: 7}, ‘Letters’: {4: ‘B’}}
Posted Date:-2021-12-31 09:56:25